Question 950135
"standard form"?   


{{{(3x+2)(x-6)=0}}}
{{{3x^2+2x-18x-12=0}}}
{{{3x^2-16x-12=0}}}
-
a=3
b=-16
c=-12


You could try to avoid Completing the Square process since your equation is given as factored.
Roots are -2/3  and 6.
Symmetry axis is in the middle.
{{{(-2/3+6)/2}}}
{{{(5&1/3)/2}}}
{{{(16/3)/2}}}
{{{16/6}}}
{{{highlight_green(x=8/3)}}} Axis of Symmetry, FOR THE FUNCTION, not just the given equation.


y for the vertex:  {{{(3(8/3)+2)((8/3)-6)}}}
{{{10*(8/3-18/3)}}}
{{{10(-10/3)}}}
{{{highlight_green(-100/3)}}}-----?



Finish by filling in the standard form information.
{{{highlight(3(x-8/3)^2-100/3=0)}}},
?