Question 950146
For the problem: R(x)= -x^5+5x^3-4x 
I got the y-int to be (0,0) by setting x=0 
And then I got the x-int to be(0,0),(2,0),(-2,0),(1,0),(-1,0) by setting the entire problem to 0. 
like -x(x^4-5x^2+4) 
(x^2-4)(x^2-1)=0 
But I checked my graphing calculator and it states that only 1,0 is present and (-0.8,0). Why isn't -1,-2,2 present and where does -0.8 come from?
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You have made some error with your graphing calculator.
Find the intersection of R(x) = y = 0 and you will 
see the x-intercepts.
Cheers,
Stan H.
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