Question 80624
4xoverx^2-9multiplied by x-3over8x^2+12x
:
{{{4x/(x^2 - 9)}}} * {{{(x-3)/(8x^2 + 12x)}}}
:
We can factor here; (x^2-9) is the difference in squares, factor out 4x also
{{{4x/((x-3)(x+3))}}} * {{{(x-3)/(4x(2x + 3))}}}
:
Cancel (x-3)'s and 4x, leaving us with:
{{{1/(x+3)}}} * {{{1/(2x+3)}}} = {{{1/((x+3)(2x+3))}}} = {{{1/(2x^2 + 9x + 9))}}}
:
How about this, can you see what we did here; any questions?