Question 949987
{{{9y=x-16}}}
{{{y=x/9-16/9}}}
A perpendicular line would have a slope that is the negative reciprocal of this line's slope.
{{{m[p]=-1/(1/9)=-9}}}
So then using the point-slope form of a line,
{{{y-(-1)=-9(x-7)}}}
{{{y+1=-9x+63}}}
{{{y=-9x+62}}}
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{{{drawing(300,300,-2,10,-10,2,grid(1),circle(7,-1,0.3),graph(300,300,-2,10,-10,2,x/9-16/9,-9x+62))}}}