Question 950051
PROBLEM 1:
{{{3x^2-10x-8=0}}}*[invoke quadratic "x", 3, -10, -8 ]
ANSWER: The positive solution is 4.

PROBLEM 2:
b=base; h=height; a=area=1/2(b)(h)
{{{a=(1/2)bh}}}
{{{56 in^2=(1/2)(2x+4)(x+3)}}}
{{{56 in^2=(x+2)(x+3)}}} 
{{{56in^2=x^2+5x+6))) Subtract 56 sq in from each side.
{{{0=x^2+5x-50}}}*[invoke quadratic "x", 1, 5, -50 ]
Our answer is the positive solution. ANSWER: The value of x is 5.