Question 949891
Find range to function: S(t) = ^4√(t^2+16) in interval form. That is a fourth root in the square root symbol. 
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rewrite equation:{{{y=(t^2+16)^(1/4)}}}
interchange y and t and solve for y
{{{t=(y^2+16)^(1/4)}}}
{{{t^4=(y^2+16)}}}
y^2=t^4-16
y=±√t^4-16)
t^4-16≥0
t^4≥16
t≥2
Range of function: [2,∞)