Question 949780
#2 .
You can pick any point for center on the y axis you want.

Taking standard form,
{{{(x-s)^2/b^2+(y-k)^2/a^2=1}}}


{{{(x-s)^2/6^2+(y-k)^2/20^2=1}}}

The center IS ON the y-axis, so s=0.
{{{highlight(x^2/6^2+(y-k)^2/20^2=1)}}}


If you are trying to say that the center IS THE ORIGIN,  (0,0), the you have
{{{highlight(highlight(x^2/6^2+(y)^2/20^2=1))}}}.
This should be understandable enough for you to draw the graph.



#1:


Simplify this, which is according to the definition for a parabola:
{{{sqrt((x-c)^2+(y-0)^2)=sqrt((x-(-c))^2+(y-y)^2)}}}