Question 80827
(x-3)^2=9
Write it as follows:
[(x-3)^2-9]=0
This is the difference of squares:
Factor as follows:
[x-3-3][x-3+3]=0
[x-6][x]=0
x=0 or x=6
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Another way to do it:
Expand it to get:
x^2-6x+9-9=0
x^2-6x=0
x(x-6)=0
x=0 or x=6
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Cheers,
Stan H.