Question 949692
e = Esthers age
i = Isabel's age
:
Write an equation for each statement.
:
Esther's age is one year more than twice Isabela's age.
e = 2i + 1
:
 Eight years ago, the sum of their ages was equal to Esther's age 10 years hence.
(e-8) + (i-8) = e + 10
e + i - 16 = e + 10
e + i = e + 10 + 16
e + i = e + 26
subtract e from both sides; therefore
i = 26 yrs is Isabel's age
then
e = 2(26) + 1
e = 53 yrs is Esther's age
:
;
see if that checks out in the statement
"Eight years ago, the sum of their ages was equal to Esther's age 10 years hence."
45 + 18 = 53 + 10
63 = 63
:
How old are they now? 26 and 53