Question 949464
(x(1),y(1))=(5,3); (x(2),y(2))=(1,6)
d=distance between points
{{{d=sqrt((x(2)-x(1))^2+(y(2)-y(1))^2)}}}
{{{d=sqrt((1-5)^2+(6-3)^2)}}}
{{{d=sqrt(16+9)}}}
{{{d=sqrt(25)}}}
d=5 ANSWER The length of the line segment with endpoints (5,3) and (1,6) is 5.