<PRE><B>Question 949541</B>
The length of a rectangle is three times its width. If the perimeter of the rectangle is 64m, find its area
W=width; L=length=3W; P=perimeter=2(L+W)
P=2(L+W)
64m=2(L+W) Divide each side by 2.
32 m=L+W Substitute for L.
32 m=3W+W
32m=4W Divide each side by 4.
8m=W The width is 8 meters.
L=3W=3(8 m)=24 m The length is 24 meters.
A=L*W=24 m*8 m=192 sq m ANSWER: The area is 192 square meters.</PRE>