Question 949408
Solve the equation below for all values of theta On the interval 0(degrees) is less than or equal to theta which is less than or equal to 360(degrees) 
2tan^2theta -3tan theta -5=0
{{{2tan^2(x)-3tanx-5=0}}}
(2tanx-5)(tanx+1)=0
..
2tanx-5=0
tanx=5/2
x=68.2˚, 248.2˚ (in quadrants I and IV where tan>0)
or
tanx+1=0
tanx=-1
x=135&#730;, 225&#730;  (in quadrants II and III where tan<0)