Question 949343

Hi!

I have been trying to solve this problem quite a while, and help for solving this would be great. 

In a strict monarchy there are 100 monks, either senior or junior. If a senior monk is allowed to have 3 slices of break for each meal, and a junior monk is only allowed 1/3 of a slice, and altogether the consume 60 slices of break during lunch, how many senior monks are there?

I know that the answer is 10, but I was just wondering how it is possible to come to that answer.

Thank you!
<pre>You must be referring to BREAD here, and not BREAK

Let number of senior monks be S
Then number of junior monks = 100 – S
We then get: {{{3S + (1/3)(100 - S) = 60}}}
{{{3S + (100 - S)/3 = 60}}}
9S + 100 – S = 180 ---------- Multiplying by LCD, 3
9S – S = 180 – 100
8S = 80
S, or number of senior monks = {{{80/8}}}, or {{{highlight_green(10)}}}