Question 949222

{{{x^2-6x + 9 = 11}}} 
{{{x^2-6x + 3^2 = 11}}} 
{{{(x-3)^2 = 11}}} 
{{{sqrt((x-3)^2) = sqrt(11)}}} 

solutions:
{{{(x-3) = sqrt(11)}}} or {{{-(x-3) = sqrt(11)}}}

if {{{x-3 = sqrt(11)}}}=>{{{x = sqrt(11)+3}}}

if {{{-(x-3) = sqrt(11)}}}=>  {{{-x+3 = sqrt(11)}}}=>  {{{3- sqrt(11)=x}}} or   {{{x=3- sqrt(11)}}}

so, your answer are options:
A.	{{{x = -sqrt (11) + 3}}}
D.	{{{x = sqrt (11) +  3}}}