Question 80388
Since we have an equation of y we can substitute {{{2x-4}}} into y of the first equation


{{{8x-4(2x-4) = 16}}} substitute {{{2x-4}}} into y


{{{8x- 4*2x-4(-4) = 16}}} Distribute


{{{8x- 8x+16 = 16}}} Multiply


{{{16 = 16}}} Combine like terms. Since this is true for any x, we have an infinite number of solutions (note: having infinite solutions is not the same as having no solutions at all. So even though the previous poster said there were no solutions I'm sure s/he meant there isn't one solution only)