Question 949258
A-first card is not a face card
B-second card is a face card
P(A_and_B)=P(A)*P(B|A)
P(B|A)=P(A_and_B)/P(A)
There are 12 face cards in a standard deck.
{{{P(A)=(52-12)/52=10/13}}}
{{{P(B)=12/51}}}
{{{P(A_and_B)=P(A)*P(B)=(10/13)(12/51)=40/221}}}
So then, 
P(B|A)={{{(40/221)/(10/13)}}}
P(B|A)={{{highlight(12/51)}}}