Question 949135
{{{B+3=2(A+3)}}}
{{{B+3=2A+6}}}
1.{{{B-2A=3}}}
.
.
.
{{{B-6=3(A-6)}}}
{{{B-6=3A-18}}}
2.{{{B-3A=-12}}}
Subtract eq. 1 from eq. 2,
{{{B-3A-B+2A=-12-3}}}
{{{-A=-15}}}
{{{A=15}}}
Then,
{{{B-30=3}}}
{{{B=33}}}