Question 948688
How would I solve for the vertex, directrix and focus coordinates of this parabola? 
x^2 − 32y = 0 
x^2=32y
This is an equation of a parabola that opens upward.
Its basic form of equation:(x-h)^2=4p(y-k), (h,k)=coordinates of the vertex
vertex: (0,0)
axis of symmetry: x=0 or y-axis
4p=32
p=8
focus: (0,8) (p-distance above vertex on the axis of symmetry)
directrix: y=-8  (p-distance below vertex on the axis of symmetry)