Question 948695
Find the focus and directrix of the parabola 
y = 3x^2 
please explain
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This is a parabola that opens up.
vertex: (0,0)
axis of symmetry: x=0 or y-axis
Its basic form: x^2=4py
x^2=(1/3)y
4p=1/3
p=1/12
focus: (0,1/12) (p distance above vertex on the axis of symmetry)
directrix: y=-1/12  (p distance below vertex on the axis of symmetry)