Question 948836
Ian and Lindsey are riding bikes in the same direction.
 Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm.
 Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm.
 At what time will Lindsey catch up with Ian?
:
From the information given we know that at 3:30 Lindsey is 10 minutes behind Ian
find the distance Lindsey travels in 10 min
{{{10/60}}}*(16) = {{{8/3}}} mi Lindsey is behind Ian at 3:30
:
Let t = time required by L to catch I (in hrs)
then
16t = dist traveled by L
12t = dist traveled by I
:
Write a distance equation,
 L has to travel 8/3 of a mile more that Ian in the same time,
16t = 12t + {{{8/3}}}
16t - 12t = {{{8/3}}}
4t = {{{8/3}}}
t = {{{8/3}}}*{{{1/4}}}
t = {{{8/12}}} hr; which is {{{8/12}}}*60 = 40 min
:
3:30 + :40 = 4:10 L catches I