Question 948946
For a triangle,
{{{A=(1/2)bh=64}}}
{{{bh=128}}}
.
.
.
{{{b=2h}}}
Substituting,
{{{(2h)h=128}}}
{{{h^2=64}}}
{{{h=8}}}{{{in}}}
So then,
{{{b=2h}}}
{{{b=16}}}{{{in}}}