Question 948767
N-nickels
D-dimes
Q-quarters
.
.
.
Total value of coins
{{{5N+10D+25Q=960}}}
.
.
"5 more dimes than nickels" 
{{{D=N+5}}}
"2 times more quarters than nickels"
{{{Q=2N}}}
Substitute these two into the first equation.
{{{5N+10(N+5)+25(2N)=960}}}
{{{5N+10N+50+50N=960}}}
{{{65N+50=960}}}
{{{65N=910}}}
{{{N=14}}
So then,
{{{D=14+5}}}
{{{D=19}}}
and
{{{Q=2(14)}}}
{{{Q=28}}}