<PRE><B>Question 948696</B>
 Find three consecutive integers
n, (n+1), (n+2)
:
such that three times the sum of the first and the last is 552.
3(n + (n+2)) = 552
3(2n + 2) = 552
6n + 6 = 552
6n = 552 - 6
6n = 546
n = 546/6
n = 91 is the 1st integer, then obviously, 92 and 93
:
:
Check this
3(91 + 93) =
3 * 185 = 552</PRE>