Question 948428

A person drove 24 mph on a trip. If he had driven 36 mph he would have arrived 2 hours earlier.  What was the distance traveled?
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Let distance driven, be D
Then time taken = {{{D/24}}}
Time he/she would’ve taken had he/she driven 36 mph: {{{D/36}}}
With difference in time being 2 hours, we get: 
{{{D/24 = D/36 + 2}}}
3D = 2D + 144 ------- Multiplying by LCD, 72
3D – 2D = 144
D, or distance traveled = {{{highlight_green(144)}}} miles