Question 948336
Solve 2x 3y=17 and 5x 6y=32
lets have the same value of x
5(2x 3y=17)
2(5x 6y=32)
:-  10x 15y=35
   -(10x 12y=64)
:- 3y=-29
     y=-29/3
then chose one equesion and substitute for y
2x 3(-29/3)=17
2x-29=17
2x=17 29=46
2x=46
x=23
:- the value of x is     23 and y is -29/3.