Question 948331
X=first integer; X+1=second integer
(X)(X+1)=5(X+(X+1))-25
{{{X^2+X=5X+5X+5-25}}}
{{{X^2+X=10X-20}}} Subtract 10X from each side.
{{{X^2-9X=-20}}} Add 20 to each side.
{{{X^2-9X+20=0}}}
*[invoke quadratic "X", 1, -9, 20 ]
ANSWERS form X are 4 and 5
CHECK
For X=4, X+1=5
4(5)=5(4+5)-25
20=45-25
20=20 True, so 4 is a correct answer. ANSWER 1: One pair of consecutive integers is 4,5
For X=5, X+1=6
5(6)=5(5+6)-25
30=55-25
30=30 So 5 is also a correct answer. ANSWER 2: Another pair of consecutive integers is 5,6.
So there are two pairs of consecutive integers that fulfill these requirements, (4,5) and (5,6).