Question 948282
When you added the 4 in the parentheses, you were really adding {{{(1/2)4=2}}}.
Well you subtracted 4 but it should have been 2.
So,
{{{G(t)=(1/2)(t^2-4t+4)-2}}}
{{{G(t)=(1/2)(t-2)^2-2}}}
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X-intercepts: Set {{{y=0}}} solve for {{{x}}}.
{{{0=(1/2)(t^2-4t)}}}
{{{0=(1/2)(t(t-4))}}}
So then {{{t=0}}} and {{{t=4}}} are the x-intercepts (or the t-intercepts).
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Y-intercept : Set {{{t=0}}} solve for {{{y}}}.
{{{y=0}}}
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{{{drawing(300,300,-2,6,-4,4,grid(1),circle(0,0,0.2),circle(4,0,0.2),circle(2,-2,0.2),graph(300,300,-2,6,-4,4,(1/2)(x^2-4x)))}}}