Question 948035
From eq. 1,
{{{2x=6-4y}}}
{{{x=-2y+3}}}
Substituting into eq. 2,
{{{3(-2y+3)+6y-9=0}}}
{{{-6y+9+6y-9=0}}}
{{{0=0}}}
True, but not actually yielding a solution.
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Eq. 1 is actually a multiple of eq. 2,
{{{(3/2)(2x+4y-6)=(3/2)(0)}}}
{{{3x+6y-9=0}}}
So, they are the same equation so there are infinitely many solutions.