Question 948203
Let East be positive x and North be positive y.
Then starting from ({{{0}}},{{{0}}}), pilot first goes 300km East.
({{{0}}},{{{0}}})+({{{300}}},{{{0}}})=({{{300}}},{{{0}}})
Then 300km NE,
({{{300}}},{{{0}}})+({{{300cos(45)}}},{{{300sin(45)}}})=({{{300}}},{{{0}}})+({{{212.1}}},{{{212.1}}})=({{{512.1}}},{{{212.1}}})
So the plane has traveled 512.1 miles East.
The angle that the bearing makes with the x-axis would be found using the tangent.
{{{tan(theta)=212.1/512.1=0.4142}}}
{{{theta=22.5}}}
So I'm assuming that the bearing you need is from North (positive y) which would be,
{{{90-22.5=67.5}}}