Question 948197
{{{y+z=1}}}
{{{x+y-z=1}}}
{{{(1+sqrt(2))x=sqrt(2)}}}
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{{{A=(matrix(3,3,0,1,1,1,1,-1,(1+sqrt(2)),0,0))}}}
{{{abs(A)=-(2+2*sqrt(2))}}}
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{{{A[x]=(matrix(3,3,1,1,1,1,1,-1,sqrt(2),0,0))}}}
{{{abs(A[x])=-2sqrt(2)}}}
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{{{A[y]=(matrix(3,3,0,1,1,1,1,-1,(1+sqrt(2)),sqrt(2),0))}}}
{{{abs(A[y])=-(2+sqrt(2))}}}
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{{{A[z]=(matrix(3,3,0,1,1,1,1,1,(1+sqrt(2)),0,sqrt(2)))}}}
{{{abs(A[z])=-sqrt(2)}}}
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{{{x=abs(A[x])/abs(A)=(-2sqrt(2))/(-(2+2sqrt(2)))=2-sqrt(2)}}}
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{{{y=abs(A[y])/abs(A)=(-(2+sqrt(2)))/(-(2+2sqrt(2)))=sqrt(2)/2}}}
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{{{z=abs(A[z])/abs(A)=(-sqrt(2))/(-(2+2sqrt(2)))=1-sqrt(2)/2}}}