Question 948174
{{{P=n-2}}}
{{{Q=n}}}
{{{R=n+2}}}
{{{3P=2R-3}}}
Substituting,
{{{3(n-2)=2(n+2)-3}}}
{{{3n-6=2n+4-3}}}
{{{3n-6=2n+1}}}
{{{n=7}}}
So then,
{{{R=7+2}}}
{{{R=9}}}