<PRE><B>Question 948106</B>
A salesperson has a 20% chance of making a sale to any customer who is called upon. If 6 calls are made, what is the probability that
 A- three sales are made?
P(x = 3) = 6C3*0.2^3*0.8^3 = binompdf(6,0.2,3) = 
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 B- at least one sale is made?
P(1&lt;= x &lt;=6) = 1 - P(x = 0) = 1 - 0.8^6 = 
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 C- Find the mean of the distribution
u = np = 6*0.2 = 1.2
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 D-find the standard deviation of the distriubtion
std = sqrt(npq) = sqrt(1.2*0.8) = 0.979
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Cheers,
Stan H.
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