Question 947946
 for each planet in a solar system, its year is the time it takes the planet to revolve around the center star.
 the formula E= 0.2X^3/2 models the number of the earth days in a planet's year,E, where x is the average distance of the planet from the center star,in millions of kilometers. 
 there are approximately 88 Earth days in the year of the planet mercury.What is the average distance of mercury from the star?
 
{{{.2x^(3/2)}}} = 88; the exponents is 3/2
{{{x^(3/2)}}} = {{{88/.2}}}
{{{x^(3/2)}}} = 440
{{{log(x^(3/2))}}} = log(440)
log equiv of exponents, find the log of 440
{{{(3/2)*log(x)}}} = 2.64345
log x = {{{2/3}}} * 2.64345
log x = 1.7623
x = 57.85 ~ 58 million km is the av distance between the sun and mercury