Question 948014
Write the first trigonometric function in terms of the second for θ in the given quadrant.
sec θ, sin θ; θ in Quadrant III
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cos  &#952;=-&#8730;(1-sin^2( &#952;))=-1/sec  &#952; (in quadrant III where cos<0)
sec  &#952;=-1/&#8730;(1-sin^2( &#952;))