Question 947987

{{{y = 4x -3}}}.......eq.1
{{{y = 5x -1}}}.......eq.2
------------------------------substitute {{{5x -1}}} for {{{y}}} in eq.1
 	
{{{5x -1 = 4x -3}}}.......eq.1...solve for {{{x}}}

{{{5x -4x = 1 -3}}}

{{{highlight(x = -2)}}}

go to {{{y = 5x -1}}}.......eq.2 substitute {{{-2}}} for {{{x}}} and solve for {{{y}}}

{{{y = 5(-2) -1}}}

{{{y = -10 -1}}}

{{{highlight(y = -11)}}}

solution is:

D. ({{{-2}}}, {{{-11}}})