Question 947834
1.1) s(0) = 48, s(0) represents the height above the ground when the object is released
1.2) s is 0
0 = -16t^2 + 32t + 48
using quadratic formula to solve equation, we have
t = -1 or t = 3, we want the positive value t = 3
which means the object will hit the ground in 3 seconds
1.3) 0 < or = t < or = 3
1.4) graph of -16t^2 + 32t + 48
{{{ graph( 300, 200, -5, 5, -10, 100, -16x^2+32x+48) }}} 
1.5) set t = the axis of symmetry
t = -b/2a = -32 / (2*(-16)) = 1, max height at 1 second
s(1) = -16 +32 +48 = 64, max height is 64