Question 947774

Use logarithms to solve the given equation. (Round the answer to four decimal places.)
9(1.09^(2x + 1)) = 15
<pre>
{{{9(1.09^(2x + 1)) = 15}}}
{{{1.09^(2x + 1) = 15/9}}}
{{{1.09^(2x + 1) = 5/3}}}
{{{log (1.09, (5/3)) = 2x + 1}}}
{{{2x + 1 = (log (5/3))/log(1.09)}}}
{{{2x = (log (5/3))/log(1.09)}}}{{{- 1}}}
{{{x = (log (5/3))/log(1.09)}}}{{{- 1}}}{{{"÷"}}}{{{2}}}
x = {{{2.463793}}} &#8776; {{{highlight_green(2.4638)}}}