Question 947803
Write the following quadratic function in the vertex form and identify the vertex.
 y=3x^2+6x-2
 3*(x^2+2)-2
 3*(x^2+2-2)2-3
 Vertex(-1,-1) Am I on the right path?
-------
y = 3x^2 + 6x -2
--------
y+2 = 3(x^2+2x)
------
3(x^2+2x+1) = y + 2 + 3
---
3(x+1)^2 = y + 5
----
Vertex:: (-1,-5)
-------
{{{graph(400,400,-10,10,-10,10,3x^2+6x-2)}}}
---------------
Cheers,
Stan H.
---------------