Question 947763

{{{y=x^2-3x-2}}} ...easiest way to solve this is to set {{{y=0}}} and use quadratic formula


{{{0=x^2-3x-2}}} ...coefficients are: {{{a=1}}},{{{b=-3}}}, and {{{c=-2}}} 

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


{{{x = (-(-3) +- sqrt( (-3)^2-4*1*(-2)))/(2*1) }}}


{{{x = (3 +- sqrt( 9+8))/2 }}}

{{{x = (3 +- sqrt( 17))/2 }}}

exact solutions:

{{{x = (3 + sqrt( 17))/2 }}}

or

{{{x = (3- sqrt( 17))/2 }}}


approximate solutions:

{{{x = (3 + sqrt( 17))/2 }}}

{{{x = (3 + 4.12)/2 }}}

{{{x = 7.12/2 }}}

{{{x = 3.56 }}}

or

{{{x = (3 - sqrt( 17))/2 }}}

{{{x = (3 -4.12)/2 }}}

{{{x = -1.12/2 }}}

{{{x =-0.56 }}}


{{{ graph( 600,600, -10, 10, -10, 10, x^2-3x-2) }}}