Question 947733

{{{(2b-2)/(2b^2-8)}}}

{{{2(b-1)/2(b^2-4)}}}

{{{cross(2)(b-1)/cross(2)(b^2-2^2)}}}

{{{(b-1)/((b-2)(b+2))}}}

to have a solution, we need to exclude all values of {{{b}}} that make denominator equal to zero, and they are

{{{(b-2)(b+2)=0}}} 
if {{{(b-2)=0}}}=>{{{b=2}}}
if  {{{(b+2)=0}}} =>{{{b=-2}}}

the solution set is { {{{x}}} | {{{x}}} is a real number and {{{x<>2}}} and {{{x<> -2}}}  }

or

({{{-infinity}}},{{{-2}}}) U ({{{-2}}},{{{2}}}) U ({{{2}}},{{{infinity}}})