Question 947700
let a be the event that truck 1 is available.
let b be the event that truck 2 is available.


p(a) is given as .76
p(b) is given as .55
p(a and b) is given as .46


p(a or b) = p(a) + p(b) - p(a and b) = .76 + .55 - .46 = .85


not p(a or b) is equal to 1 - p(a or b) = 1 - .85 = .15


probability that neither truck is available is .15 based on this formula.