Question 947630
Form two equations based on the formula.


{{{system(22+C*b^0=96,22+C*b^10=50)}}}


{{{system(Cb^0=74,C*b^10=28)}}}


Some simplification more


{{{C*1=74}}}
{{{highlight(C=74)}}}
and 
{{{highlight(C*b^10=28)}}}


C now known, and b is easily found.