Question 947621
Let X=smallest number, X+1 the next, X+2 the third
X+(X+1)+(X+2)=498
3X+3=498 Subtract 3 from each side
3X=495 Divide each side by 3
X=165 ANSWER 1: The smallest number is 165
X+1=166 The middle number is 166
X+2=167 The largeest number is 167
CHECK
Sum is 498
165+166+167=498
498=498