Question 947615
Check discriminant:  {{{(-13)^2-4*6*2=169-48=121=11^2}}}


General solution for quadratic equation for roots:  {{{(13+- sqrt(11^2))/12}}},
{{{(13+- 11)/12}}}
{{{1/6}}}  and  {{{2}}}


You want the parts of the parabola greater than 0.


Solution is {{{x<1/6}}}  or  {{{x>2}}}.

Interval Notation:   (-infin, 1/6)  or  (2, infinity)