Question 947602


to factor {{{7x^2-25x+12=0}}} first replace {{{-25x}}} with {{{-21x-4x}}}

{{{7x^2-21x-4x+12=0}}} ...group

{{{(7x^2-21x)-(4x-12)=0}}}...factor out {{{7x}}} from first group and {{{4}}} from second group

{{{7x(x-3)-4(x-3)=0}}}

{{{(7x-4)(x-3)=0}}}

now you can find solutions easier:

if {{{(7x-4)=0}}}=>{{{7x=4}}}=>{{{x=4/7}}}

if {{{(x-3)=0}}}=>{{{x=3}}}