Question 947605



{{{x^2-9x+18=0}}}


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} to use the quadratic formula to solve for, note that {{{a=1}}},{{{b=-9}}}, and {{{c=18}}}; so, plug it in

{{{x = (-(-9) +- sqrt( (-9)^2-4*1*18 ))/(2*1) }}} 


{{{x = (9 +- sqrt( 81-72 ))/2 }}}  


{{{x = (9 +- sqrt( 9 ))/2 }}}


{{{x = (9 +- 3)/2 }}}

solutions:

{{{x = (9 + 3)/2 }}}

{{{x = 12/2 }}}

{{{x = 6 }}}

or

{{{x = (9 - 3)/2 }}}

{{{x = 6/2 }}}

{{{x = 3 }}}


{{{ graph( 600, 600, -10, 10, -10, 20, x^2-9x+18) }}}