Question 947536

Selena has some nickels, dimes and quarters. She has 1½ times as many dimes as nickels. She has 5 fewer quarters than nickels. If Selena has a total of $5.05, how many of each coin does she have?
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Let number of nickels be N
Then number of dimes = {{{(1&1/2)N}}}, or {{{(3/2)N}}}, or {{{3N/2}}}
Number of quarters = N - 5 
We then have: {{{.05N + .1(3N/2) + .25(N - 5) = 5.05}}}
{{{.05N + .3N/2 + .25N - 1.25 = 5.05}}}
{{{.05N + .25N + .3N/2 = 5.05 + 1.25}}}
{{{.3N + .3N/2 = 6.3}}}
.6N + .3N = 12.6 -------- Multiplying by LCD, 2
.9N = 12.6
N, or number of nickels = {{{12.6/.9}}}, or {{{highlight_green(14)}}}
Number of dimes: {{{(3/2)14}}}, or {{{highlight_green(21)}}}
Number of quarters: 14 – 5, or {{{highlight_green(9)}}}