Question 947528
r for radius


{{{r=sqrt((-1-0)^2+(-2-2)^2)}}}
{{{sqrt((1)^2+(0)^2)}}}
{{{sqrt(1)}}}
{{{r=1}}}


EQUATION:  {{{highlight((x+1)^2+(y+2)^2=1)}}}


The small blue curve mark is the location for the center point of the circle.
{{{graph(300,300,-3,3,-3,3,-2-sqrt(1-(x+1)^2),-2+sqrt(1-(x+1)^2),-2+sqrt(0.003-(x+1)^2))}}}