Question 947506
Find the minimum y-value located on the graph of y=2x^2-6x+1.
<pre>{{{y = 2x^2 - 6x + 1}}}
Its minimum will occur at the x-coordinate of the vertex, or the axis of symmetry, or where: {{{x = - b/2a}}}.
When found, substitute this x-value into the equation to get y: the minimum value.