Question 947456

I've been working on this problem for hours and still can't seem to find a solution, could you please help if possible?

A person drives to a destination at a rate of thirty mph and returns over the same route at fifty mph. How far is the destination if the time returning is one hour less than the time going?
<pre>
Let the distance be D
Then outbound time = {{{D/30}}}
Inbound time = {{{D/50}}}
Therefore, {{{D/30 - 1 = D/50}}}
5D – 150 = 3D ------ Multiplying by LCD, 150
5D – 3D = 150
2D = 150
D, or distance = {{{150/2}}}, or {{{highlight_green(75)}}} mph